php - Another tricky preg_match -

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Only one paragraph contains "stop word", it needs to be seen, stop words are in the array below.

I have the formula: 

  $ pattern_array = array ("beforehand", "min", "stir", "summer", "put", "beat "," Bowl "," pan "); Foreign currency ($ pattern_array $ as pattern) {If (preg_match ('/'. Pattern $. '' / I ', $ paragraph)) {$ stopwords = 1; }}

Which works quite well, but the word 'panko' is termed as a stop word for the term 'pan'.

So the reges will be something in which it has a place or a new line is up and the ending in the full term / space / comma / (other non-eligible objects).

How do I tell PHP other than this? As soon as a stop word is detected, to exit the loop?

Thanks guys, learning to slow down as I go!

Use \ b (preheat | minutes | stir | heat | Put | bowl | pan) \ b In the same way as your regex, you only need a regex (no looping required), and claiming the \ b word boundary , You ensure that only match the whole words.


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