c# - Creating a class for JSON deserialization -

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निम्नलिखित JSON पर विचार करें: 

  {"code": 2, "body": {"डायनामिक-कुंजी": {"कुंजी 1": "वैल 1", "कुंजी 2": "वैल 2"}}}

निम्नलिखित क्लास संरचना को परिभाषित करना: 

  [DataContract] वर्ग JsonResponse {[DataMember] सार्वजनिक स्ट्रिंग कोड {get; सेट; } [डेटामेम्बर] सार्वजनिक जेसन रीस्पॉन्स बॉडी बॉडी {प्राप्त; सेट; }} [डेटा कॉन्ट्रैक्ट] वर्ग जेसन रीस्पॉन्सबॉडी [[डेटामेम्बर (नाम = "डायनेमिक-कुंजी")] सार्वजनिक डायनामिक किडाडेटा डेटा {प्राप्त; सेट; }} [डेटाकांट्रक्ट] वर्ग डायनैमिककीडेटा {[डेटामेम्बर] सार्वजनिक स्ट्रिंग कुंजी 1 {प्राप्त करें; सेट; } [डेटामेम्बर] सार्वजनिक स्ट्रिंग कुंजी 2 {प्राप्त; सेट; }}

मैं दिए गए JSON को निम्न कोड के साथ deserialize कर सकता हूँ: 

  DataContractJsonSerializer serializer = नया डेटा कंट्रैक्टजसन सेरियलाइज़र (टाइपफ (जेसनईरेस्पॉन्स)); JsonResponse प्रतिक्रिया डेटा = serializer.ReadObject (responsestream) JsonResponse के रूप में;

हालांकि मेरे मामले में "डायनामिक-कुंजी" ज्ञात नहीं है और उपयोगकर्ता इनपुट वैल्यू द्वारा परिभाषित किया गया है। इस तरह की JSON परिभाषा को संभालने का सही तरीका क्या है?

विचार:

JSON एक तृतीय पक्ष एपी का है, इसलिए इसे बदलना नहीं है एक विकल्प।

मेरे मामले में मुझे डायनामिक-कुंजी नाम की परवाह नहीं है, इसलिए यदि हमेशा एक सामान्य नाम को मैप करने का कोई विकल्प होता है तो यह काम करेगा।

> अग्रिम धन्यवाद।

क्या आपको निश्चित रूप से WCF का उपयोग करने की आवश्यकता है? अन्यथा मैं देख रहा हूँ की सिफारिश की

जैसे कई एक्सटेंसिबिलिटी मैकेनिज़्म हैं

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