asp.net - How to make linkbutton control in gridview open an new ie window -

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मुझे 

  & lt; asp: TemplateField HeaderText = "ename" & gt; & Lt; आइटममेटलेट & gt; & Lt; asp: Label ID = "lbl2" text = '& lt;% # Eval ("आईडी")% & gt; Runat = "सर्वर" & gt; & Lt; / एएसपी: लेबल & gt; & Lt; / ItemTemplate & gt; & Lt; EditItemTemplate & gt; & Lt; एएसपी: टेक्स्ट बॉक्स आईडी = "टेक्स्टबॉक्स 1" टेक्स्ट = '& lt;% # Eval ("name")% & gt;' Runat = "सर्वर" & gt; & lt; / asp: टेक्स्ट बॉक्स & gt; & Lt; एएसपी: लिंकबटन आईडी = "लिंक 1" टेक्स्ट = '& lt;% # Eval ("name")% & gt;' Runat = "सर्वर" & gt; & lt; / asp: LinkButton & gt; & Lt; / EditItemTemplate & gt; & Lt; / एएसपी: TemplateField & gt;

मेरे पास हालत (<)

के आधार पर आइटमटैप्लेट संपादित करें में एक टेक्स्टबॉक्स और लिंक बटन है (यदि टेक्स्ट = '& lt;% # ईवाल ("आईडी")%> ')

आईडी = 1 शो टेक्स्टबॉक्स [वस्तु temalpate संपादित करें]

आईडी = 2 शो लिंक बटन [आइटम temalpate संपादित करें]

< P> आईडी = 3 शो लिंक बटन [आइटम temalpate संपादित करें]

अब लिंक बटन में मेरे पास [text = '& lt;% # Eval ("name")% & gt;'] < / कोड> (उदाहरण: www.stackoverflow.com, google.com) ताकि एक उपयोगकर्ता लिंक बटन पर क्लिक करता है और एक नई ब्राउज़र विंडो खोलता है और यह दिखाता है कि लिंक बटन के क्लसीके पर एक नई ब्राउज़र विंडो खोलने के लिए वेबसाइट शो < / P>

क्या आप एक लिंकबटन के बजाय नियंत्रण का उपयोग कर सकते हैं?

उदाहरण के लिए 

  और एटीपी: हाइपरलिंक आईडी = "हाइपरलिंक 1" नेविगेट यूआरएल = "& lt;% # Eval ('name')% & gt;" पाठ = "& LT;% # Eval ( 'नाम')% & gt;" लक्ष्य = "_ रिक्त" runat = "server" / & gt;

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