php - How to take out the first part of array? -

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निम्नलिखित फ़ंक्शन एक सरणी और HTML को आउट-डालता है।

मुझे < / P> 

  & lt; li & gt; & lt; a href = "http://127.0.0.1/ci_okadadesign/index.php/admin/menus/r" & gt; आर एंड एलटी; / ए & gt; & lt; / li & gt ;  
  function getTopMenus () {$ data [0] =   
 'जड़'; $ इस- & gt; db- & gt; जहां ( 'parentid', 0); $ क्यू = $ यह- & gt; डीबी- & gt; प्राप्त करें ('मेनू'); यदि ($ Q- & gt; num_rows () & gt; 0) {foreach ($ Q- & gt; परिणाम_अरे ($ पंक्ति के रूप में) {$ डेटा [] = $ पंक्ति; }} $ Q- & gt; फ्री_रल्ट (); $ डेटा वापसी; }  
 
 प्रिंट_आर (): 
 
  अर्रे ([0] = & gt; अर्रे ([आईडी] = & gt; 24 [नाम] = & gt; मेन मेनू [shortdesc] = & gt; मुख्य मेन्यू [स्थिति] = & gt; सक्रिय [पेरेन्टिड] = & gt; 0) [1] = & gt; अरे ([आईडी] = & gt; 25 [नाम] = & gt; गैलेरी 1 [shortdesc] = & Gt; गैलेरी 1 [स्थिति] = & gt; सक्रिय [माता-पिता] = & gt; 0))  
 
 HTML: 
 
  
  •  gt; & lt; a href = "http://127.0.0.1/ci_okadadesign/index.php/admin/menus" & gt; मेनू & lt; / a & gt; & LT; ul & gt; & Lt; li & gt; & lt; a href = "http://127.0.0.1/ci_okadadesign/index.php/admin/menus/r" & gt; आर एंड एलटी; / ए & gt; & lt; / li & gt; & Lt; li & gt; & lt; a href = "http://127.0.0.1/ci_okadadesign/index.php/admin/menus/mainmenu" & gt; मुख्य मेनू & lt; / a & gt; & lt; / li & gt; & Lt; li & gt; & lt; a href = "http://127.0.0.1/ci_okadadesign/index.php/admin/menus/galleri1" & gt; गैलेरी 1 & lt; / a & gt; & lt; / li & gt; & Lt; / ul & gt;  
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    ऐसा लगता है कि आपके डेटाबेस में परिभाषित मेनू आइटम का एक समूह है यदि वहां एक मेनू आइटम है जिसमें 'आर' नाम दिया गया है, तो आपको केवल उस पंक्ति को हटाना होगा और वह और <लि> दूर जाएंगे


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